intlFormatDistance

// What is the distance between the dates when the fist date is after the second?
intlFormatDistance(
  new Date(1986, 3, 4, 11, 30, 0),
  new Date(1986, 3, 4, 10, 30, 0)
)
//=> 'in 1 hour'

// What is the distance between the dates when the fist date is before the second?
intlFormatDistance(
  new Date(1986, 3, 4, 10, 30, 0),
  new Date(1986, 3, 4, 11, 30, 0)
)
//=> '1 hour ago'

// Use the unit option to force the function to output the result in quarters. Without setting it, the example would return "next year"
intlFormatDistance(
  new Date(1987, 6, 4, 10, 30, 0),
  new Date(1986, 3, 4, 10, 30, 0),
  { unit: 'quarter' }
)
//=> 'in 5 quarters'

// Use the locale option to get the result in Spanish. Without setting it, the example would return "in 1 hour".
intlFormatDistance(
  new Date(1986, 3, 4, 11, 30, 0),
  new Date(1986, 3, 4, 10, 30, 0),
  { locale: 'es' }
)
//=> 'dentro de 1 hora'

// Use the numeric option to force the function to use numeric values. Without setting it, the example would return "tomorrow".
intlFormatDistance(
  new Date(1986, 3, 5, 11, 30, 0),
  new Date(1986, 3, 4, 11, 30, 0),
  { numeric: 'always' }
)
//=> 'in 1 day'

// Use the style option to force the function to use short values. Without setting it, the example would return "in 2 years".
intlFormatDistance(
  new Date(1988, 3, 4, 11, 30, 0),
  new Date(1986, 3, 4, 11, 30, 0),
  { style: 'short' }
)
//=> 'in 2 yr'